Respuesta :
[tex]\\ \sf\longmapsto \dfrac{4x+2}{x-9}=\dfrac{3}{5}[/tex]
[tex]\\ \sf\longmapsto 5(4x+2)=3(x-9)[/tex]
[tex]\\ \sf\longmapsto 20x+10=3x-27[/tex]
[tex]\\ \sf\longmapsto 20x-3x=-27-10[/tex]
[tex]\\ \sf\longmapsto 17x=-37[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{-37}{17}[/tex]
Answer:
[tex]\frac{4x+2}{x-9}[/tex] = [tex]\frac{3}{5}[/tex]
5( 4x+ 2 ) = 3 ( x-9 )
20x + 10 = 3x - 27
20x -3x = -27 -10
17x = -37
x = - 37/17