Question

calculate the mass of iron (iii) carbonate that will be formed when 15.0 mL of 0.15 M iron (iii) chloride solution are reacted with 20.0 mL of 0.15 M sodium carbonate. Be sure to write the balanced metathesis reaction that is occuring.

Answer 1

Answer:

The molar mass of a substance is calculated as the mass of a given chemical compound or substance, which is then divided by the amount of the substance. The mass is calculated in grams and the amount of the substance is calculated in mol. Thus, the standard unit for molar mass is g/mol.

Explanation:

According to the given question, the reaction between iron chloride and sodium carbonate will be given as:  

$\text {3Na_{2}CO_{3}\text} \;\[+\] \;\text{ 2FeCl_{3} \text}\; \rightarrow\; \text {6NaCl}\; \[+\] \;\text { Fe_{2} (CO_3)_{3} \text}$

Now, to calculate the mass of iron carbonate formed in the above chemical reaction, it will be given as:

${ \text Moles\;of}\text \;\text {FeCl_{3} \text} \[=\dfrac{0.15 \;\text {moles} \times 0.015\; \text L}{1.0 { \;\text L}\text}$

                         

                          $=\;0.00225\; \text {moles}\text$

Similarly, for sodium carbonate

$\text Moles\; of\; Na_{2}CO_{3}}\te \[=\]\dfrac{0.15 \;\text {moles} \times 0.020\; \text L}{1.0 { \;\text L}\text}$

                         

                             $\[=\]\;0.0003\; {\text moles \text}$

Limiting reactant is $\text {FeCl_{3} \text}$

Now, calculating iron chloride mass:

$=\dfrac{0.00225 \times 1\;\text{moles}\;\text{Fe}_2 {(\text{CO}_3)}}{2\;\rm{moles\;of\;}Fecl_3}$

$=0.001125 \;\text {moles }$

Now, molar mass of the $\text{Fe}_{2}\text{CO}_{3}$  will be  $=291.71679\;\text{g/ mol}$

$\begin{aligned}\text{Mass}&=\frac{\text{Moles}}{\text{Molar mass}}\\\\&=\frac{0.001125\;\text{moles}}{291.71679\; \text{g/mol}} \\\\&=3.85648\times10^{-6} \end{aligned}$