contestada

-3x + 6y = 18
-3x = 6y+14

a) What is the slope of the 1st equation?

b) What is the slope of the 2nd equation?

c) Are they parallel, perpendicular, or neither?

Respuesta :

Step-by-step explanation:

-3x + 6y = 18

-3x = 6y+14

a) the slope of the 1st equation = -(-3)/6 = ½

b) the slope of the 1st equation = -3/6 = -½

c) they are niether parallel nor perpendicular

Answer:

a)  ¹/₂

b)  -¹/₂

c)  neither

Step-by-step explanation:

Slope-intercept form of a linear equation:

[tex]y=mx+b[/tex]

where:

  • m is the slope
  • b is the y-intercept

Given equations:

[tex]\begin{cases}-3x+6y=18\\-3x=6y+14 \end{cases}[/tex]

To find the slopes of the given equations, rearrange them to make y the subject then compare with the slope-intercept formula:

Equation 1

[tex]\begin{aligned}-3x+6y & = 18\\6y & = 3x + 18\\y & = \dfrac{3x+18}{6}\\\implies y & = \dfrac{1}{2}x+3\end{aligned}[/tex]

Therefore, the slope of Equation 1 is ¹/₂.

Equation 2

[tex]\begin{aligned}-3x & = 6y+14\\6y & = -3x-14\\y & = \dfrac{-3x-14}{6}\\\implies y& = -\dfrac{1}{2}x-\dfrac{14}{6}\end{aligned}[/tex]

Therefore, the slope of Equation 2 is -¹/₂.

Parallel slopes have the same slope.

Perpendicular slopes are at right angles to each other and therefore the product of their slopes is -1 (negative reciprocals of each other).

Therefore, the slopes of Equation 1 and Equation 2 are neither parallel or perpendicular.

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