Question

please help me, if you help then thanks!

Answer 1

Answer:

Student 1 and Student 3

Step-by-step explanation:

For student 1: ✔

${x}^{2} = 64 \\ x = \sqrt{64} \\ x = {}^{ + } 8 \: \: and \: \: {}^{ - } 8$

For student 2: ❎

${x}^{3} = 1 \\ x = \sqrt[3]{1} \\ x = {}^{ + } 1$

For student 3: ✔

${x}^{2} = 9 \\ x = \sqrt{9} \\ x = {}^{ + } 3 \: \: and \: \: {}^{ - } 3$

For student 4: ❎

${x}^{3} = 216 \\ x = \sqrt[3]{216} \\ x = {}^{ + } 6$