Answer:
[tex] {x}^{2} + 5x = - 2[/tex]
arrange the equation according to general formula;
General formula: ax² + bx + c = 0
therefore:
[tex] {x}^{2} + 5x + 2 = 0[/tex]
Using the quadratic equation :
[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ [/tex]
a » 1, b » 5, c » 2
substitute:
[tex]x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 1 \times 2) } }{(2 \times 1)} \\ \\ x = \frac{ - 5± \sqrt{17} }{2} [/tex]
therefore solutions are;
[tex]{ \boxed{ \boxed{x_{1} = \frac{ - 5 + \sqrt{17} }{2} }}} \: \: and \: \: { \boxed{ \boxed{x_{2} = \frac{ - 5 - \sqrt{17} }{2} }}}[/tex]
x is -0.438 and -4.562