Respuesta :

Answer:

[tex] {x}^{2} + 5x = - 2[/tex]

arrange the equation according to general formula;

General formula: ax² + bx + c = 0

therefore:

[tex] {x}^{2} + 5x + 2 = 0[/tex]

Using the quadratic equation :

[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ [/tex]

a » 1, b » 5, c » 2

substitute:

[tex]x = \frac{ - 5± \sqrt{ {5}^{2} - (4 \times 1 \times 2) } }{(2 \times 1)} \\ \\ x = \frac{ - 5± \sqrt{17} }{2} [/tex]

therefore solutions are;

[tex]{ \boxed{ \boxed{x_{1} = \frac{ - 5 + \sqrt{17} }{2} }}} \: \: and \: \: { \boxed{ \boxed{x_{2} = \frac{ - 5 - \sqrt{17} }{2} }}}[/tex]

x is -0.438 and -4.562

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