If 5cm and 3cm are added to the length and width of a square, the perimeter of the resulting rectangle is between twice and three times the perimeter of the original square. Find the possible lengths of the sides of the original square.

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Answer:

The answer is between 2 and 4. 2 and 4 can be included if you are including the twice or three times. If it doesn't include those then it would only be anything inbetween.

Step-by-step explanation:

So to start off I would always give placeholder for all the sides. Lets label it x.

2(x+5) + 2(x+3) < 3(4x)

In the equation above, we created a simple equation with 2 representing 2 sides each and the 3 and 5 plugged in. That all is going to be less than 3 times the original perimeter which is 4x for the 4 sides.

2x + 10 + 2x + 6 < 12x

4x + 16 < 12x

16 < 8x

2 < x

We learn that the original x is greater than 2. We don't say it is equal to since it says between. Which doesn't usually include the number stated.

Now we repeat, just instead of 3 its 2 and instead of less than its greater than.

2x + 10 + 2x + 6 > 8x

4x + 16 > 8x

16 > 4x

4 > x

So your answer is between 2 and 4.

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