Question

Write in standard form.
y^2+14y-5x+64=0

Answer 1

let's solve :

$\hookrightarrow \: {y}^{2} + 14y - 5x + 64 = 0$

$\hookrightarrow \: 5x = {y }^{2} + 14y + 64$

$\hookrightarrow \: 5x = {y}^{2} + 14y + 49 + 15$

$\hookrightarrow \: 5x = (y + 7) {}^{2} + 15$

$\hookrightarrow \: x = \dfrac{(y + 7) {}^{2} + 15 }{5}$

$\hookrightarrow \: x = \dfrac{1}{5} (y + 7) {}^{2} + 3$

therefore, the correct option is B

Answer 2

Answer:

x = (1/5)(y + 7)² + 3

Step-by-step explanation:

Given that,

→ y² + 14y - 5x + 64 = 0

Let's find the required solution,

→ y² + 14y - 5x + 64 = 0

→ 5x = y² + 14y + 64

→ 5x = y² +14y +49 + 15

→ 5x = (y + 7)² + 15

→ x = [(y + 7)² + 15]/5

→ [x = (1/5)(y + 7)² + 3]

Hence, it is the correct answer.