Answer:
see explanation
Step-by-step explanation:
Using the rules of exponents
[tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1
5 (a)
[tex]7^{-6}[/tex] = [tex]\frac{1}{7^{6} }[/tex]
(b)
[tex]\frac{1}{10^{-3} }[/tex] = 10³
(6)
27[tex]x^{0}[/tex][tex]y^{-2}[/tex] ← substitute x = 4 , y = 3
= 27[tex]4^{0}[/tex][tex]3^{-2}[/tex]
= 27 × 1 × [tex]\frac{1}{3^{2} }[/tex]
= 27 × [tex]\frac{1}{9}[/tex]
= 3
