Question

an oil storage tank ruptures and oil leaks from the tank at a rate of r(t)= 100e^(-0.01t) liters per minute. How much oil leaks out during the first hour?

Answer 1

Answer:

Step-by-step explanation:

$\\\displaystyle V=\int\limits^{60}_0 {100*e^{-0.01*t}} \, dx \\\\=-\frac{100}{0.01} *\Bigg [e^{-0.01*t}\Bigg ]^{60}_0\\\\=-10000*(e^{-0.60}-1)\\\\=4511.883663.... (liters)$