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Geometry
1). In the diagram below, DAE and FBCG are parallel lines. AC = BC and angle FBA = 130°.

a)calculate the vàlues of p,q,r, and t.​

Geometry1 In the diagram below DAE and FBCG are parallel lines AC BC and angle FBA 130acalculate the vàlues of pqr and t class=

Respuesta :

Answer:

Step-by-step explanation:

∠FBA = 130°

∠FBA + p = 180      {Linear pair}

130 + p = 180

        p = 180 - 130

p = 50°

AC = BC  ⇒  r = p   {angles opposite to equal sides are equal}

r = 50°

r + q = ∠FBA  {external angle of a Δ equals sum of opposite internal angles}

50 +q = 130

        q = 130 - 50

        q = 80°

DE // FG , AC is transversal.

t = q   {alternate interior angles}

t = 80°

DE // FG , AB is transversal.

s = p  {alternate interior angles}

s = 50°

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