Question

The length of a rectangle is nine inches less than twice the width. If the perimeter of the rectangle is 84 inches, find the dimensions of the rectangle.

Please help its algebra

Answer 1

Answer:

Length = 25; Width = 17

Step-by-step explanation:

Perimeter: 2x - 9 + 2x - 9 + x + x = 84

Solve for x:

   Combine like terms:

   6x - 18 = 84

   Add 18 to both sides

   6x = 102

   Divide both sides by 6

   x = 17

Check work by plugging in 17 for x in perimeter equation

2(17) - 9 + 2(17) - 9 + 17 + 17 = 84

34 - 9 + 34 - 9 + 34 = 84

25 + 25 + 34 = 84

50 + 34 = 84

84 = 84