Answer:
(5z-6w)(5z+6w)
Step-by-step explanation:
Hi there!
We're given the expression 25z²-36w² and we want to factor it.
The expression written as a difference of squares. The difference of squares is given as a²-b²=(a-b)(a+b)
Let's label the values of what is a² and b², and then try to determine what a and b are from that information
[tex]a^{2}=25z^2\\b^2=36w^2[/tex]
Alright then! Let's square root both sides to find what a and b are
[tex]\sqrt{a^2}=\sqrt{25z^2[/tex]
Which then means:
a=5z
And then for b:
[tex]\sqrt{b^2}=\sqrt{36w^2}[/tex]
b=6w
Now substitute those values into the formula
a²-b² = (a-b)(a+b)
[tex]25z^{2}-36w^2=(5z-6w)(5z+6w)[/tex]
Hope this helps!