Respuesta :

The rational expressions that sum to  [tex]\frac{2x+3}{(x+3)(x-5)} = \frac{2x}{(x+3)(x-5)} + \frac{3}{(x+3)(x-5)}[/tex]

The given expression is:

[tex]\frac{2x+3}{x^2-2x-15}[/tex]

Factorize the denominator

[tex]x^2-2x-15\\x^2-5x+3x-15\\x(x-5)+3(x-5)\\(x+3)(x-5)[/tex]

The given expression therefore becomes:

[tex]\frac{2x+3}{(x+3)(x-5)}[/tex]

This can be split into the sum:

[tex]\frac{2x+3}{(x+3)(x-5)} = \frac{2x}{(x+3)(x-5)} + \frac{3}{(x+3)(x-5)}[/tex]

Learn more here: https://brainly.com/question/17103002

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