neroa5
neroa5 neroa5
  • 29-08-2021
  • Mathematics
contestada

Someone help me with #12

Someone help me with 12 class=

Respuesta :

s403167
s403167 s403167
  • 29-08-2021

Answer:

12.

[tex]x = \frac{PQ-14}{3}[/tex] and [tex]x = \frac{QR + 10}{7}[/tex]

Step-by-step explanation:

Hope this helps!

Have a nice day! :-)

Answer Link
c62712
c62712 c62712
  • 29-08-2021

Answer:

x = 6

Step-by-step explanation:

If PQ = 3x + 14, QR = 7x - 10, and Q is the midpoint of PR, then PQ = QR.

[tex]PQ = 3x + 14 = QR = 7x - 10\\3x + 14 = 7x - 10\\3x + 24 = 7x\\24 = 4x\\6 = x\\x = 6[/tex]

Answer Link

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