Answer:
[tex] {ax}^{3} + 4ax \\ [/tex]
factorise out a and x :
[tex] { \boxed{answer{= ax( {x}^{2} + 4) }}}\\ but \: farther \: more : \\ = ax( {x}^{2} + {2}^{2} )[/tex]
but from general factorization:
[tex]{ \boxed{( {a}^{2} + {b}^{2}) = {(a + b)}^{2} - 2ab }}[/tex]
a » x
b » 2
therefore:
[tex] = ax \{ {(x + 2)}^{2} - 2(x)(2) \} \\ \\ = { \boxed{ \boxed{ax( {x + 2)}^{2} - 4x }}}[/tex]
