Question

how many moles of LiOH are needed to react completely with 25.5 g of CO2

Answer 1

Answer:

3.18 mol

Explanation:

$2LiOH+CO_{2}-> Li_{2}CO_{3} +H_{2}O$

n(CO2) = mass/ Mr.

             = 25.5 / 16

             = 1.59 mol

As per the equation above,

n(LiOH) : n(CO2)

     2      :    1

∴  3.18   :  1.59