Question

There are 21 apples,28 pears and 49 oranges. These are to be arranged in heaps containing the same number of fruits. Find the greatest number of fruits possible to keep in each heap. How many heaps are formed by this arrangement?​

Answer 1

21+28+49= 98 (fruit)
98/49=2

2 heaps can be formed.
Each would have 49 fruit.

Answer 2

Answer:

greatest no. of fruits possible to keep in each heap is 7

no. of heaps is 14

Step-by-step explanation:

21 apples

28 pears

49 oranges.

$28 \div 21$quotient will be 1 and 7 remainder

$21 \div 7$

quotient will be 3 and 0 remainder

$49 \div 7$

quotient will be 7 and 0 remainder

hence, the greatest number of fruits is 7

Now,no. of heaps formed to keep fruits

Apple = 21

Pear = 28

Orange =49

Now, 21+28+49 = 98

Then, one heap can store can 7 fruits

Then,let the no. of heaps be x

x= 98÷7

x=14

Hence, no. of heaps = 14