Question

What is the correct formula for finding the 6th power of a complex number in polar form?

Answer 1

Answer:

Step-by-step explanation:

Let $z=r\cos \theta + i\sin \theta$

then by the Moivre

$z^6 = r^6 \left( \cos \theta +i\sin \theta)^6= r^6\left(\cos (6\theta) + i\sin(6\theta)\right)$