[tex]\begin{array}{l}\text{We\ have\ } \alpha +\beta =90\ \text{and} \ \beta =\alpha +32\text{\ then}\\\\\alpha +\alpha +32=90\\\\\Longrightarrow 2\alpha =90-32\\\\\Longrightarrow \alpha =\frac{58}{2} =29\\\\\therefore \beta =29+32=61\\\\\therefore \boxed{\text{The\ larger\ angle\ is\ 61\ degrees}}\end{array}[/tex]