Question

For what value of k is the trinomial x2 - 6x + k a perfect square?

Answer 1

Answer:

9

Step-by-step explanation:

$x^2-6x+k\\= x^2-6x + 9 + (-9)+k\\=(x-3)^2+k-9$

So in order this expression to be a perfect square we need k-9=0. Thus k =9.