Question

6 Σ n=1 n/2n + 1
Ignore the selected answer, I accidentally clicked, please help

Answer 1

Answer:

Answer is the second circle will explain later but the second circle the middle one

Answer 2

$\begin{array}{l}\sum _{n=1}^{6}\frac{n}{2n+1} =\frac{1}{2\cdotp 1+1} +\frac{2}{2\cdotp 2+1} +\frac{3}{2\cdotp 3+1} +\frac{4}{2\cdotp 4+1} +\frac{5}{2\cdotp 5+1} +\frac{6}{2\cdotp 6+1}\\\\\sum _{n=1}^{6}\frac{n}{2n+1} =\frac{1}{3} +\frac{2}{5} +\frac{3}{7} +\frac{4}{9} +\frac{5}{11} +\frac{6}{13}\end{array}$