Respuesta :

Answer:

Step-by-step explanation:

1. The first one is equivalent since

[tex]\sqrt{48}=\sqrt{16\cdot 3}-\sqrt{16}\cdot \sqrt{3}=4\sqrt{3}.[/tex]

2. It is not equivalent

[tex]\sqrt{75}=\sqrt{25\cdot 3}=\sqrt{25}\cdot \sqrt{3}=5\sqrt{3}\neq 7\sqrt{5}[/tex]

3. It is equivalent

[tex]-\sqrt{360}=-\sqrt{4\cdot 90}=-\sqrt{4}\cdot \sqrt{90}=-2\sqrt{90}.[/tex]

ACCESS MORE