Answer:
Step-by-step explanation:
Note that
[tex]\frac{\sqrt{5}}{3}=\frac{5\sqrt{5}}{15}\\\frac{3}{5}=\frac{9}{15}[/tex]
Since
[tex](5\sqrt{5})=125 > 81 = 9^2, \text{ then }\\\frac{5\sqrt{5}}{15} >\frac{9}{15}[/tex]
So
[tex]\frac{3}{5} < \frac{\sqrt{5}}{3}[/tex]
Now clearly
[tex]\frac{\sqrt{5}}{3} < 1 < 27, 5 < 97 < 97\pi[/tex]
Therefore
[tex]\frac{3}{5} < \frac{\sqrt{5}}{3} < 27,5 < 97\pi[/tex]
