Respuesta :

Answer:

Step-by-step explanation:

Note that

[tex]\frac{\sqrt{5}}{3}=\frac{5\sqrt{5}}{15}\\\frac{3}{5}=\frac{9}{15}[/tex]

Since

[tex](5\sqrt{5})=125 > 81 = 9^2, \text{ then }\\\frac{5\sqrt{5}}{15} >\frac{9}{15}[/tex]

So

[tex]\frac{3}{5} < \frac{\sqrt{5}}{3}[/tex]

Now clearly

[tex]\frac{\sqrt{5}}{3} < 1 < 27, 5 < 97 < 97\pi[/tex]

Therefore

[tex]\frac{3}{5} < \frac{\sqrt{5}}{3} < 27,5 < 97\pi[/tex]

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