Question

One number is 9 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 848, find the numbers
The three numbers are needed

Answer 1

Answer:

$first \: no \: 9x \\ second \: numberx \\ third \: no9x + 100 \\ 9x + x + 9x + 100 = 848 \\ 19x + 100 = 848 \\ 19x = 848 - 100 \\ \\ 19x = 748 \\ \\ x = 39.4$

Step-by-step explanation:

9×+×+100+9×=848

19×+100=848

19×=848-100

19×=748

×=39.4

9×=354.6

9×+100=354.6+100=454.6