Respuesta :
Answer:
First equation
from definition of acceleration:
[tex]a = \frac{change \: in \: velocity}{time} \\ \\ a = \frac{v - u}{t} \\ \\ at = v - u\\ { \boxed{v = u + at}}[/tex]
Second equation
from displacement:
[tex]s = (average \: velocity) \times time \\ s = ( \frac{v + u}{2} ) \times t \\ \\ 2s = (v + u)t[/tex]
but v is u + at :
[tex]2s = \{(u + at) + u \} \times t \\ \\ 2s = (2u + at)t \\ 2s = 2ut + {at}^{2} \\ s = \frac{2ut}{2} + \frac{a {t}^{2} }{2} \\ \\ { \boxed{s = ut + \frac{1}{2} {at}^{2} }}[/tex]
third equation
from displacement:
[tex]s = ( \frac{v + u}{2} )( \frac{v - u}{a} ) \\ \\ 2as = (v + u)(v - u) \\ 2as = {v}^{2} - {u }^{2} \\ \\ { \boxed{ {v}^{2} = {u}^{2} + 2as }}[/tex]
s » displacement
v » final velocity
u » initial velocity
a » acceleration
t » time
Answer:
The answer is given above Hii nitin it's me bhul gye meko Tom,shivi guess kro kon xd
