Pls need help solving this.

Answer:
Step-by-step explanation:
Given: ABC is equilateral triangle.
AD = DB & BE = EC & CF = FA ------------(IV)
Proof:
D & F are midpoint of the sides AB and AC
DF = [tex]\frac{1}{2}BC[/tex] {Midpoint theorem}
DF = BE ----------------(I)
D & E are midpoint of the sides AB and BC
DE = [tex]\frac{1}{2}AC[/tex] {Midpoint theorem}
DE = FA ----------------(II)
E & F are midpoint of the sides BC and AC
[tex]EF = \frac{1}{2}AB[/tex] {Midpoint theorem}
EF = AD ---------------(III)
From (I) ; (II) ; (III) ; (IV) ,
DF = DE = EF
DEF is an equilateral triangle.