Respuesta :

Answer:

Step-by-step explanation:

Given: ABC is equilateral triangle.

AD = DB   & BE = EC   & CF = FA ------------(IV)

Proof:

  D & F are midpoint of the sides AB and AC

  DF = [tex]\frac{1}{2}BC[/tex]            {Midpoint theorem}    

DF = BE     ----------------(I)

D & E are midpoint of the sides AB and BC

DE = [tex]\frac{1}{2}AC[/tex]               {Midpoint theorem}      

DE = FA ----------------(II)

E & F are midpoint of the sides BC and AC

[tex]EF = \frac{1}{2}AB[/tex]                  {Midpoint theorem}

EF = AD   ---------------(III)

From (I) ; (II) ; (III) ; (IV) ,

DF =  DE = EF

DEF is an  equilateral triangle.

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