Respuesta :
[tex]\text{h}=5 \ \text{and} \ \text{j}=3 \ \text{and} \ \text{k}=7\\\\\frac{\text{h}}{5}-\text{h}(\text{k}+\text{j})=\frac{5}{5}-5\cdot(3+7)=1-5\cdot10=1-50=\boxed{-49}[/tex]
[tex]\text{h}=5 \ \text{and} \ \text{j}=3 \ \text{and} \ \text{k}=7\\\\\frac{\text{h}}{5}-\text{h}(\text{k}+\text{j})=\frac{5}{5}-5\cdot(3+7)=1-5\cdot10=1-50=\boxed{-49}[/tex]