Answer:
Step-by-step explanation:
Doing this the long way, write a^12 as a product of "a"s
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
Now group them into groups of 4
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
There are 3 groups of 4 so you can write it as [(a^4)]^3 which is a cube
Now do the same thing with groups of 6s
a^12 = a * a * a * a * a * a * a * a * a * a * a * a
a^12 = (a^6)^2
So the two answers are
Perfect cube: [(a^4)]^3
Perfect square: (a^6)^2
