contestada

given PR with P(-6, -6) and R(-2, 10), if Q lies on PR such that the ratio of PQ to PR is 5:8 find the coordinates of Q

Respuesta :

Lines can be divided into segments using ratios. The coordinates of Q when PR is divided into 5:8 is [tex](-4.462,0.154)[/tex]

Given that:

[tex]P (x_1,y_1) = (-6,-6)[/tex]

[tex]R (x_2,y_2) = (-2,10)[/tex]

[tex]m:n = 5:8[/tex] --- the ratio

The coordinate of Q is calculated using the following line ratio formula

[tex]Q = \frac{1}{m+n}(mx_2 + nx_1,my_2 + ny_1)[/tex]

So, we have:

[tex]Q = \frac{1}{5+8}(5\times -2 + 8\times -6,5\times 10 + 8\times -6)[/tex]

[tex]Q = \frac{1}{5+8}(-58,2)[/tex]

[tex]Q = (-58/13,2/13)[/tex]

[tex]Q = (-4.462,0.154)[/tex]

Hence, the coordinates of Q is [tex](-4.462,0.154)[/tex]

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