Question

In the course of an afternoon walk, Mr. Hooper met,
consecutively, 10 friends, and every one of them was
wearing a hat. They greeted each other by tipping their
hats. Il people wearing
1. How many times was that done?
2. How many times would those hats have been lifted
if their owners had met simultaneously?
a hat.

Answer 1

The number of times hats were tipped for consecutive meetings = 10

The number of times hats were tipped for simultaneous meeting is once

The Number of friends Mr. Hooper met = 10

Since they met consecutively (one after the other) ;

Then ;

Two hats are tipped per meeting (that if Mr. Hooper and the friend he met)

For 10 consecutive meetings :

This means, the action was performed 10 times :

Hence, the number of times two hats were tipped is 10 times.

Hence, 20 hats were lifted.

2.)

If the owners met simultaneously :

Then, the owners all met at the same time,

Tipping of the hat will be performed only once.

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