Question

The perimeter of a rectangular tray is 28 inches. The length of the tray is 2 inches longer the width of the tray. Determine the dimensions of the rectangular tray.

Answer 1

Step-by-step explanation:

perimeter=28

length=2x

width=x

28=2(x+2x)

28=2x+4x

28=6x

28/6=6x/6

4.67=x

width=4.67

length=2×4.67

=9.34

Answer 2

Using the concept of perimeter of a rectangle, we have that:

• The length is of 8 inches.
• The width is of 6 inches.

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Perimeter of a rectangle:

The perimeter of a rectangle of length l and width w is given by:

$P = 2(l + w)$

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The perimeter is of 28 inches, thus:

$P = 28$

$2(l + w) = 28$

Dividing both sides by 2:

$l + w = 14$

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The length is 2 inches longer than the width, thus:

$l = 2 + w$

Replacing into the equation, we find the width:

$2 + w + w = 14$

$2w = 12$

$w = \frac{12}{2}$

$w = 6$

The width is of 6 inches.

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The length is:

$l = 2 + w = 2 + 6 = 8$

The length is of 8 inches.

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