Question

Calculate the distance between the points J = (- 2, - 1) and A = (3, - 7) in the coordinate plane Round your answer to the nearest hundredth

Answer 1

Answer:

The distance between the points is 7.81 (to the nearest hundreth)

Step-by-step explanation:

The distance formula between two points in the coordinate plane is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Put,

$J(x_1,y_1)=(-2,-1)\\A(x_2,y_2)=(3,-7)$

Hence,

$d=\sqrt{(3-(-2))^2+(-7-(-1))^2} \\d=\sqrt{(3+2)^2+(-7+1)^2} \\d=\sqrt{5^2+(-6)^2} \\d=\sqrt{25+36} \\d=\sqrt{61} \\d=7.810$