Question

I need help with #41 and #42 ASAP please help me.. please show step by step I need to get it done soon because It is due

Answer 1

Answer:

Step-by-step explanation:

41)

$1+2+3+4+...+n=\dfrac{(n+1)*n}{2} \\\\2+4+6+...+2n=2*(1+2+3+4+...+n)=2*\dfrac{(n+1)*n}{2} =(n+1)*n$

42)

the square of the sum of the first n natural integers equals the sum of the cubes of these