Question

Two cars leave towns 760 kilometers apart at the same time and travel toward each other. One car's rate is 20 kilometers per hour less than the other's. If they meet in 4 hours, what is the rate of the slower car?

Answer 1

Answer:

Let speed of slower car be xkm/h

Therefore rate of other car=x+20 km/h

After 4 hrs ,

Distance covered by Car A=4x

Distance covered by Car B=4x+80

4x+4x+80=760km

8x=680

x=45

The rate of the slower car=45km/h