Respuesta :
At the start, there are a total of 19 marbles. The chance of pulling one red is 8/19 (because there are 8 red).
Based on the way you stated the questions, I do not assume the red marble that was pulled first would be put back, so there’s only 18 marbles left to choose from and 7 of those are red. So on the second marble, you have 7/18 chance of pulling a red.
Again, since neither of the first two marbles were put back, you now have 17 marbles left and 6 of those are red. So you have a 6/17 chance of pulling a third red marble.
Multiply those together, 8/19 * 7/18 * 6/17 and you’ll have your answer.
Based on the way you stated the questions, I do not assume the red marble that was pulled first would be put back, so there’s only 18 marbles left to choose from and 7 of those are red. So on the second marble, you have 7/18 chance of pulling a red.
Again, since neither of the first two marbles were put back, you now have 17 marbles left and 6 of those are red. So you have a 6/17 chance of pulling a third red marble.
Multiply those together, 8/19 * 7/18 * 6/17 and you’ll have your answer.
Answer:
NO. OF RED =8
NO. OF BLUE=4
NO. OF GREEN=7
THEREFORE,TOTAL MARBLES=19
THEREFORE,PROBABILTY OF RED MARBLES=8/19.