Question

Find the radius and the center of the circle with the given equation x^2+y^2−8x−2y=48.

Answer 1

Step-by-step explanation:

x²+y²−8x−2y=48

the radius => √[(8/2)² + (2/2)² +48] =

√(16+1+48) =√65

the center => (8/2, 2/2)

=> (4, 1)