Question

2) If a wet sponge weighs 59.3 grams and the
Same spinge when dry, weighs 15.8 grams,
what percent of the initial weight comes from water?

Answer 1

The percentage of water in the wet sponge is 73.34%.

AMOUNT (IN GRAMS) OF WATER IN THE SPONGE:

• According to this question, a wet sponge weighs 59.3 grams. However, when dried, the sponge weighs 15.8 grams.

• This means that the mass (amount) of water in the original sponge is as follows:

59.3 - 15.8

= 43.5 grams.

• The percentage of water in the initial mass of the sponge can therefore, be calculated as:

% mass of water = (mass of water ÷ mass of wet sponge) × 100

% mass of water = 43.5/59.3 × 100

% mass of water = 0.73335 × 100

% mass of water = 73.34%

Therefore, the percent of the initial weight that comes from water is 73.34%

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