Answer:
[tex] \boxed{d = \frac{5}{3}}[/tex]
Step-by-step explanation:
[tex]given \: points \: (2,1) \: and \: (1, - \frac{1}{3}): \\ d \: = \sqrt{ (x _{2} - x_{1})^{2} +(y_{2} - y_{1})^{2} } \\ d \: = \sqrt{ (1 - 2)^{2} +( - \frac{1}{3} - 1)^{2} } \\ d \: = \sqrt{ ( - 1)^{2} +( - \frac{4}{3})^{2} } \\d \: = \sqrt{ (1) +( \frac{16}{9}) } \\d \: = \sqrt{ 1 + \frac{16}{9} } \\d \: = \sqrt{ \frac{9}{9} + \frac{16}{9} } \\d \: = \sqrt{ \frac{25}{9} }\\d \: = \frac{\sqrt{ 25 }}{\sqrt{ 9 }} \\d \: = \frac{ 5}{3} [/tex]
