An object of mass 2kg is thrown vertically downwards with an initial kinetic energy of 100J. What is the distance fallen by the object at the instant when its kinetic energy has doubled

Respuesta :

The distance fallen by the object at the instant when its kinetic energy has doubled is 5.097m

The kinetic energy of an object is the energy possessed by the body by virtue of its motion.

The gravitational potential energy (energy due to the virtue of its position) of a body is being converted to Kinetic energy once an object falls.

Using the law of conservation of energy according to the equation:

Kinectic Energy = Potential Energy

Since PE = mgh

KE = PE = mgh

Given the following parameters

KE = 100J

m = 2kg

g = 9.81m/s²

Required

Height h

Substitute the required values into the formula

100 = 2(9.81)h

h = 100/19.62

h = 5.097m

Hence the distance fallen by the object at the instant when its kinetic energy has doubled is 5.097m

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