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  • 20-08-2021
  • Mathematics
contestada

Write the equation of the line that passes through the points
(3,-2) and (6, 1).
y=x-5
y = 5x + 1
y = -x + 5

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Аноним Аноним
  • 20-08-2021

Answer:

It is y = x - 5

Step-by-step explanation:

General equation of a line:

[tex]{ \bf{y = mx + c}}[/tex]

m is the gradient, and c is y-intercept.

For gradient:

[tex]slope = \frac{y_{2} - y_{1} }{x _{2} - x_{1}} [/tex]

substitute:

[tex]slope = \frac{1 - ( - 2)}{6 - 3} \\ \\ = \frac{3}{3} \\ slope \: = 1[/tex]

m = 1

for y-intercept:

consider point (6, 1):

[tex]y = mx + c \\ 1 = (6 \times 1) + c \\ 1 = 6 + c \\ c = 1 - 6 = - 5[/tex]

therefore:

[tex]{ \sf{equation \: is \: \{y = x - 5 \}}}[/tex]

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