Question

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8. At the surface of a swimming pool a 2.0 L balloon is under 760 mmHg of pressure. If that balloon is taken to the
bottom of the deep end, the pressure is now 950 mmHg. What is the new volume of the balloon?
0.45 L
b. 1.6L
2.4 L
d. 95 L
a.
C.
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Answer 1

The new volume of the balloon is 1.6L

HOW TO CALCULATE THE FINAL VOLUME:

• Using Boyle's law, which states that the pressure of a given gas is inversely proportional to its volume i.e PV = K

Boyle's law equation is as follows:

P1V1= P2V2

Where;

• P1 = initial pressure (mmHg)
• P2 = final pressure (mmHg)
• V1 = initial volume (L)
• V2 = final volume (L)

According to this question,

P1 = 760mmHg

V1 = 2L

V2 = ?

P2 = 950mmHg

Using P1V1 = P2V2

760 × 2 = 950 × V2

1520 = 950V2

V2 = 1520/950

V2 = 1.6L

Therefore, the new volume of the balloon is 1.6L

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