Question

Please answer the question above!

Answer 1

Answer:

B) $A=4x+8$

Step-by-step explanation:

Hi there!

Area of a trapezoid: $A=\displaystyle\frac{1}{2}h(b_1+b_2)$

⇒ b₁ = x-3

⇒ b₂ = x+7

⇒ h = 4

Plug the given information into the equation:

$A=\displaystyle\frac{1}{2}(4)[(x-3)+(x+7)]\\\\A=\displaystyle\frac{1}{2}(4)(x-3+x+7)\\\\A=2(2x+4)\\\\A=4x+8$

Therefore, the area of the trapezoid is $4x+8$.

I hope this helps!