Question

for the equation given, how many grams of methane will react with a 125g of oxygen
CH4 (g) + 2O2(g) -> CO2(g) +2H2O​

Answer 1

Answer:

16

Explanation:

1) in the given equation CH₄+2O₂⇒ 2H₂O+CO₂;

M(CH₄)=12+4=16 (g/mol); M(O₂)=32 (g/mol);

2) if m(O₂)=125 gr., then ν(O₂)=m(O₂)/M(O₂)=125/32≈3.90625 (moles);

3) if in the given equation 'ν' of O₂ is 2, then the 'ν' of CH₄ is 1;

4) m(CH₄)=ν(CH₄)*M(CH₄)=1*16=16 (gr.).