Question

A car starts from rest and accelerates uniformly at a rate of 8.0 meter per second squared for 1.0 meters. At the end of this time interval, the car's final velocity is ___ meters per second.

Answer 1

Answer:

The answer is $v=4ms^{-1}$

Explanation:

Given,

$u=0\,ms^{-1}\\a=8\,ms^{-2}\\s=1\,m\\\\v=?$

We know,

∴$v^{2}=u^{2} +2as\\=>v^{2} =0^{2} +2*8*1\\=>v^{2}=16\\v=4\,ms^{-1}$

Hope you have understood this....

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