Answer:
Using the section formula, if a point (x,y) divides the line joining the points (x
1
,y
1
) and (x
2
,y
2
) in the ratio m:n, then
(x,y)=(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
3AC=CB
CB
AC
=
3
1
Since, A(1,1) and B(2,3) & m:n=1:3
Therefore, we have
C(
m+n
mx
2
+nx
1
,
m+n
my
2
+ny
1
)
(
1+3
(1)(2)+3(1)
,
1+3
(1)(3)+3(1)
)
C→(
4
5
,
2
3
).
