Question

a coach is travelling east wards at 12.6 m/s after 12 second its velocity is 9.5 m/s in the same direction. what is the acceleration and direction of its acceleration?

pls do it with the formula
thx mates :)​

Answer 1

• Initial velocity=u=12.6m/s
• Final velocity=9.5m/s
• Time=t=12s
• Acceleration be a

$\\ \rm\longmapsto a=\dfrac{v-u}{t}$

$\\ \rm\longmapsto a=\dfrac{12.6-9.5}{12}$

$\\ \rm\longmapsto a=\dfrac{3.1}{12}$

$\\ \rm\longmapsto \overrightarrow{a}=0.25m/s^2$