Answer:
1/(8a^12)
Step-by-step explanation:
(2a^4)^-3
Rewriting
2^-3 * a^4^-3
We know x^y^z = x^(y*z)
2^-3 * a^(4*-3)
2^-3 * a^-12
We know x^-y = 1/a^y
1/2^3 * 1/a^12
1/8 * 1/a^12