If SK=13x-5,KY=2x+9, and SY=36-x find each value
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Answer:
SY = SK + KY
(36 - X) = (13X - 5) + (2X + 9)
36 - X = 13X - 5 + 2X + 9
36 + 5 - 9 = 13X + 2X + X
32 = 16X
32/16 = 16/16
X = 2
ii)SK = 13X - 5
SK = 13(2) - 5
SK = 21 units
iii) KY = 2X + 9
KY = 2(2) + 9
KY = 13
iv) SY = 36 - X
SY = 36 - 2
SY = 34
The required values are X = 2, SK = 21, KY = 13, and SY = 34.
A line segment in geometry is a section of a line that has two clearly defined endpoints and contains every point on the line that lies within its confines.
Given that the segemnts are SK=13x-5,KY=2x+9, and SY=36-x. Then the value of each segment will be calculated as below:-
SY = SK + KY
(36 - X) = (13X - 5) + (2X + 9)
36 - X = 13X - 5 + 2X + 9
36 + 5 - 9 = 13X + 2X + X
32 = 16X
32/16 = 16/16
X = 2
ii)SK = 13X - 5
SK = 13(2) - 5
SK = 21 units
iii) KY = 2X + 9
KY = 2(2) + 9
KY = 13
iv) SY = 36 - X
SY = 36 - 2
SY = 34
Therefore, the required values are X = 2, SK = 21, KY = 13, and SY = 34.
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