Question

A rectangle has a length of 2 6√
and width of 6√
. Find the perimeter of the rectangle.

Answer 1

• L=2root6
• B=root6

$\\ \rm\Rrightarrow Perimeter=2(L+B)$

$\\ \rm\Rrightarrow Perimeter=2(2\sqrt{6}+\sqrt{6})$

$\\ \rm\Rrightarrow Perimeter=2(3\sqrt{6})$

$\\ \rm\Rrightarrow Perimeter=6\sqrt{6}$

Answer 2

Answer:

6sqrt(6)

BRAINLIEST, PLEASE!

Step-by-step explanation:

2sqrt(6) x 2 = 4sqrt(6)

sqrt(6) x 2 = 2sqrt(6)

4sqrt(6) + 2sqrt(6) = 6sqrt(6)