Question

Solve using any method. All work must be shown and handwritten.
3x-y=-10
x+y=-2
show how it is solved please <3

Answer 1

Answer:

$x = - 3$

$y = 1$

Step-by-step explanation:

Write the system

$3x - y = - 10$

$x + y = - 2$

Solve by Elimination.

multiply the second equation by -3.

$3x - y = - 10$

$-3x - 3y = 6$

Add the Equations.

$- 4y = - 4$

$y = 1$

Plug this back in one of the equations.

$x + 1 = - 2$

$x = - 3$

Answer 2

Answer:

x = -3

y = 1

Step-by-step explanation:

3x - y = -10

x + y = - 2

x + y = - 2

x = -y - 2

replacing in other equation

3(-y - 2) - y = -10

-3y - 6 - y = - 10

rearranging the equation

-3y - y = = -10 + 6

-4y = -4

y = 1

putting this value in first eqn we get

x - y = -2

x - (1) = -2

x = -2-1

x = -3